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The average of 5 consecutive odd numbers in descending order is 95. Find the fourth number in the descending order.

1. 95
2. 97
3. 99
4. 93

यदि अवरोही क्रम की 5 क्रमागत विषम संख्याओं का औसत 95 है, तो अवरोही क्रम की चौथी संख्या कौन सी होगी?

1. 95
2. 97
3. 99
4. 93
This Question came in
UGC-NET-English-14-June-2023-Shift-2-Q23
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If the average of 5 consecutive odd numbers in descending order is 95, then the middle number (the third number) would be the average itself, which is 95.

The five consecutive odd numbers are:

n - 4
n - 2
n (average = 95)
n + 2
n + 4
So, the third number (n) is 95. Therefore, the fourth number in the descending order would be 95−2=93.
यदि घटते क्रम में लगातार 5 विषम संख्याओं का औसत 95 है, तो मध्य संख्या (तीसरी संख्या) औसत ही होगी, जो कि 95 है।

पाँच क्रमागत विषम संख्याएँ हैं:

एन - 4
एन - 2
n (औसत = 95)
एन + 2
एन + 4
तो, तीसरी संख्या (n) 95 है। इसलिए, अवरोही क्रम में चौथी संख्या 95−2=93 होगी।
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