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If the numerator and denominator of a fraction are increased by 7, then fraction becomes 2/3. Find the original fraction.

1. 4/5
2. 3/5
3. 3/8
4. 5/3

यदि किसी भिन्न के अंश और हर में 7 की वृद्धि हो जाती है, तो भिन्न 2/3 हो जाती है । मूल भिन्न ज्ञात कीजिए ।

1. 4/5
2. 3/5
3. 3/8
4. 5/3
This Question came in
UGC-NET-Management-12-March-2023-Shift-2-Q25
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Detailed Explanation & Answer
Let the original fraction be x / y.
According to the problem, if we increase both the numerator and denominator by 7, we get the fraction (x + 7) / (y + 7), and this is equal to 2 / 3.

So, we can write:
(x + 7) / (y + 7) = 2 / 3
which results in
3x - 2y = -7

Now, we can substitute the answer choices to find the correct one:
4/5: 3(4) - 2(5) = 12 - 10 = 2 (not -7)
3/5: 3(3) - 2(5) = 9 - 10 = -1 (not -7)
3/8: 3(3) - 2(8) = 9 - 16 = -7 (matches)
5/3: 3(5) - 2(3) = 15 - 6 = 9 (not -7)

So, the correct original fraction is 3/8, which is option 3.
माना मूल भिन्न x/y है।
समस्या के अनुसार, यदि हम अंश और हर दोनों को 7 से बढ़ाते हैं, तो हमें भिन्न (x + 7) / (y + 7) मिलता है, और यह 2 / 3 के बराबर है।

तो, हम लिख सकते हैं:
(x + 7) / (y + 7) = 2/3
जिसके परिणामस्वरूप
3x - 2y = -7

अब, हम सही उत्तर खोजने के लिए उत्तर विकल्पों को प्रतिस्थापित कर सकते हैं:
4/5: 3(4) - 2(5) = 12 - 10 = 2 (-7 नहीं)
3/5: 3(3) - 2(5) = 9 - 10 = -1 (-7 नहीं)
3/8: 3(3) - 2(8) = 9 - 16 = -7 (मिलान)
5/3: 3(5) - 2(3) = 15 - 6 = 9 (-7 नहीं)

तो, सही मूल भिन्न 3/8 है, जो विकल्प 3 है।
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