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UGC-NET-Paper1

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Suppose a man swims 12 km upstream and 20 km down stream in a river in 4 hours. If he swims 18 km upstream and 10 km downstream also in 4 hours, then the speed at which he swims in the still water is.

1. 4 km /hr
2. 6 km /hr
3. 8 km /hr
4. 10 km /hr

मान लीजिए कि एक आदमी 4 घंटे में एक नदी में 12 किमी ऊपर और 20 किमी नीचे की धारा तैरता है। यदि वह 18 किमी ऊपर की ओर तैरता है और 10 किमी नीचे की ओर 4 घंटे में भी, तो जिस गति से वह अभी भी पानी में तैरता है, वह गति है।

1. 4 किमी /घंटा
2. 6 किमी /घंटा
3. 8 किमी /घंटा
4. 10 किमी /घंटा
This Question came in
UGC-NET-English-07-January-2025-Shift-2-Q40
UGC-NET Paper 1 Full Course

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Detailed Explanation & Answer
### Step 1: Define Variables
Let the speed of the man in still water be **x** km/h.
Let the speed of the river current be **y** km/h.

- **Upstream speed** = (x - y) km/h
- **Downstream speed** = (x + y) km/h

### Step 2: Form Equations
Given conditions:

1. **12 km upstream + 20 km downstream in 4 hours**
=> 12/(x - y) + 20/(x + y) = 4

2. **18 km upstream + 10 km downstream in 4 hours**
=> 18/(x - y) + 10/(x + y) = 4

### Step 3: Solve for x and y
Using elimination method:

Divide both equations by 2 to simplify:

(6/(x - y)) + (10/(x + y)) = 2
(9/(x - y)) + (5/(x + y)) = 2

Now, subtract the second equation from the first:

(6/(x - y)) - (9/(x - y)) + (10/(x + y)) - (5/(x + y)) = 0

(-3/(x - y)) + (5/(x + y)) = 0
=> 5/(x + y) = 3/(x - y)
=> 5(x - y) = 3(x + y)
=> 5x - 5y = 3x + 3y
=> 2x = 8y
=> x = 4y

### Step 4: Substitute x = 4y
Substituting in the first equation:

12/(4y - y) + 20/(4y + y) = 4
12/(3y) + 20/(5y) = 4
4/y + 4/y = 4
8/y = 4
y = 2

Now, x = 4(2) = 8

### Final Answer:
**(3) 8 km/hr**
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