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UGC-NET-Paper1

Research Aptitude

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Read the Question carefully and choose the correct option.

(n=number of trials p=probability of success)
A. n=7, p=0.3
B. n=5, p=0.4
C. n=8, p=0.5
D. n=6, p=0.6

(Variance of Binomial Distribution)
I. 1.44
II. 2.00
III. 1.20
IV. 1.47

1. A-I, B-II, C-III, D-IV
2. A-II, B-III, C-IV, D-I
3. A-III, B-IV, C-I, D-II
4. A-IV, B-III, C-II, D-I

(n=परीक्षणों की संख्या p=सफलता की संभावना)
A. n=7, p=0.3
B. n=5, p=0.4
C. n=8, p=0.5
D. n=6, p=0.6

(द्विपद वितरण का प्रसरण)
I. 1.44
II. 2.00
III. 1.20
IV. 1.47

1. A-I, B-II, C-III, D-IV
2. A-II, B-III, C-IV, D-I
3. A-III, B-IV, C-I, D-II
4. A-IV, B-III, C-II, D-I

This Question came in

UGC-NET-Linguistics-30-August-2024-Shift-1-Q10

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Detailed Explanation & Answer

A. n=7, p=0.3: Variance = 7 * 0.3 * 0.7 = 1.47 (IV)
B. n=5, p=0.4: Variance = 5 * 0.4 * 0.6 = 1.20 (III)
C. n=8, p=0.5: Variance = 8 * 0.5 * 0.5 = 2.00 (II)
D. n=6, p=0.6: Variance = 6 * 0.6 * 0.4 = 1.44 (I)

A. n=7, p=0.3: विचरण = 7 * 0.3 * 0.7 = 1.47 (IV)
B. n=5, p=0.4: विचरण = 5 * 0.4 * 0.6 = 1.20 (III)
C. n=8, p=0.5: विचरण = 8 * 0.5 * 0.5 = 2.00 (II)
D. n=6, p=0.6: विचरण = 6 * 0.6 * 0.4 = 1.44 (I)

The Correct Answer is 4

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