A. Let original fraction be x/y. After increasing numerator by 25%, numerator becomes 1.25x. Denominator increased by 50%, becomes 1.5y. New fraction is 5/3, so
(1.25x) / (1.5y) = 5/3
(1.25/1.5)(x/y) = 5/3
(5/6)(x/y) = 5/3
x/y = (5/3) / (5/6) = (5/3) × (6/5) = 2
So original fraction is 2/1 → matches IV
B. 4 1/3 - 3 1/2 = (13/3) - (7/2) = (26/6) - (21/6) = 5/6 → matches III
C. Fraction equivalent to 40% = 40/100 = 2/5 → matches II
D. 0.064 / (3.25 × 3.20 - 3.20 × 3.05) = 0.064 / (10.4 - 9.76) = 0.064 / 0.64 = 1/10 → matches I
A. मान लीजिए मूल भिन्न x/y है। अंश में 25% की वृद्धि करने पर अंश 1.25x हो जाता है। हर में 50% की वृद्धि करने पर 1.5y हो जाता है। नई भिन्न 5/3 है, अतः
(1.25x) / (1.5y) = 5/3
(1.25/1.5)(x/y) = 5/3
(5/6)(x/y) = 5/3
x/y = (5/3) / (5/6) = (5/3) × (6/5) = 2
अतः मूल भिन्न 2/1 है → मिलान IV
B. 4 1/3 - 3 1/2 = (13/3) - (7/2) = (26/6) - (21/6) = 5/6 → मिलान III
C. 40% के बराबर भिन्न = 40/100 = 2/5 → मिलान II
D. 0.064 / (3.25 × 3.20 - 3.20 × 3.05) = 0.064 / (10.4 - 9.76) = 0.064 / 0.64 = 1/10 → मेल खाता है I